(3x^4+4x^3-32x^2-x-20)/(X+4)

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Solution for (3x^4+4x^3-32x^2-x-20)/(X+4) equation: 


D( x )

X+4 = 0

X+4 = 0

X+4 = 0

X+4 = 0

x naleu017Cy do R

x belongs to the empty set

(3*x^4+4*x^3-(32*x^2)-x-20)/(X+4) = 0

x belongs to the empty set

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